Как найти количество цифр в строке питон

For counting integers only, you can use a simple regular expression:

import re
s = '2019 was a great year for 10 fortunate people in ages 20 to 60.'
n = len(re.findall(r'd+', s))  # 4

Here 'd+' means “one or more decimal characters in a row”.

Note that re.findall produces a list of the results. If you only care about the number of elements (n), this is wasteful for input strings containing very many numbers. Instead, make use of an iterator approach, e.g.

import re
s = '2019 was a great year for 10 fortunate people in ages 20 to 60.'
n = sum(1 for _ in re.finditer(r'd+', s))  # 4

Incorporating floats

Let’s say that you allow floats like 1.2 and 3e-4 etc. as well. The corresponding regular expression is now much more complicated, and an easier solution would be to just loop over all “words” in the string and check if they can be interpreted as a number:

def is_number(num):
    try:
        float(num)
    except:
        return False
    return True

s = '2019 was a great year for 10 fortunate people in ages 20 to 60.'
n = sum(1 for num in s.split() if is_number(num))  # 4

Ignoring anything else that may or may not be correct with your “revised code”, the issue causing the error currently quoted in your question is caused by calling the “count” function with an undefined variable because your didn’t quote the string.

• count(thisisastring222) looks for a variable called thisisastring222 to pass to the function called count. For this to work you would have to have defined the variable earlier (e.g. with thisisastring222 = "AStringWith1NumberInIt.") then your function will do what you want with the contents of the value stored in the variable, not the name of the variable.
• count("thisisastring222") hardcodes the string “thisisastring222” into the call, meaning that the count function will work with the exact string passed to it.

To fix your call to your function, just add quotes around asdfkasdflasdfl222 changing count(asdfkasdflasdfl222) to count("asdfkasdflasdfl222").

As far as the actual question “How to count digits, letters, spaces for a string in Python”, at a glance the rest of the “revised code” looks OK except that the return line is not returning the same variables you’ve used in the rest of the code.
To fix it without changing anything else in the code, change number and word to digit and letters, making return number,word,space,other into return digit,letters,space,other, or better yet return (digit, letters, space, other) to match current behavior while also using better coding style and being explicit as to what type of value is returned (in this case, a tuple).

На Python можно использовать функцию isdigit() из модуля string для проверки, является ли символ цифрой, и функцию sum() для подсчета количества цифр в строке.

Пример:

import string

def count_digits(s):

return sum(c.isdigit() for c in s)

s = ‘Hello, world! 123’

print(count_digits(s­)) # Output: 3

В этом примере функция count_digits() принимает строку s и возвращает количество цифр в этой строке.

Естественно, этот метод можно расширить или модифицировать в зависимости от ваших потребностей. Например, если вам нужно подсчитать количество конкретной цифры в строке, вы можете использовать метод count() строки.

s = ‘Hello, world! 123’

print(s.count(‘1’)) # Output: 1

Если вам нужно подсчитать количество цифр в нескольких строках, вы можете использовать цикл for и вызывать функцию count_digits() для каждой строки:

strings = [‘Hello, world!’, ‘abc123’, ‘123abc’]

for s in strings:

print(count_digits(s­))

Вывод:

3

3

3

Вы можете использовать эти методы или модифицировать их для решения своей задачи.