Как найти площадь полумесяца

I found this problem on a thread on Stack overflow where it was posted as “job interview question”. Unfortunately I cannot find the question. But I saved the picture and just cannot figure it out.

The problem is to calculate the area of the crescent.

asked Apr 29, 2011 at 19:33

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Here’s how I’d do it:

Call $R$ the radius of the big circle and $r$ that of the small one. Now, observe that the surface of the crescent is just the difference between the surface of the big circle and the small one or

$$pi R^2 – pi r^2 = pi (R-r)(R+r) ; .$$

Note how I’ve expressed this surface as a product of two quantities which I am now going to determine from the other data in the drawing. First the difference between the double radii is clearly 9cm:

$$2R-2r=9$$

We’re halfway. Then the distance between the center of the small circle and point E is obviously $r$, but can alternatively be expressed with Pythagoras as

$$r^2 = (R-5)^2+(r-R+9)^2 ; .$$

Reordering and using what we already know about $R-r$:

$$r^2 – (R-5)^2= left(frac{9}{2}right)^2 ; .$$

Again, using the factorizing trick

$$(r – R+5)(r+R-5)= left(frac{9}{2}right)^2 ; .$$

Thus,

$$r+R= 5+2left(frac{9}{2}right)^2 ; .$$

Combining everything, we get that the surface of the crescent is

$$pi frac{9}{2}left(5+2left(frac{9}{2}right)^2right)$$

answered Apr 29, 2011 at 20:04

found the original post here: https://softwareengineering.stackexchange.com/questions/20927/what-is-your-favorite-whiteboard-interview-problem/28439#28439

and there is the solution in the comments:

the diameters differ by 9cm, so if the inner circle has radius r, the outer circle has radius r + 4.5. The area of the crescent is the difference in the areas of the circles: pi(r + 4.5)^2 – pi * r^2. All that’s left is finding r. Define C as the point (0,0), then point E is at (0, r – 0.5) (because CE is 5cm less than the larger radius). The inner circle is shifted right 4.5cm, so its equation is (x – 4.5)^2 + y^2 = r^2. Plug in (x,y) = (0, r – 0.5) and solve for r.

For any chord passing through a point inside a circle, the product of the lengths of the sub-segments is a number depending only on the point, not the chord. (This number is called the “power” of that point, though the value itself isn’t relevant here.) That is, if any two chords contain the same point, then the products of their respective sub-segments are equal.

In your diagram —writing $E^prime$ for the reflection of point $E$ in the (presumed) diameter $AD$— we have chords $AD$ and $EE^prime$ meeting at point $P$ inside the smaller circle. Therefore,

$$CA cdot CD = CE cdot CE^prime ;;;; left(;= text{power of point};; C;right)$$

Now, let $R$ be the radius of the big circle. Then $CA = R$, $CD = R-9$, and $CE=CE^prime=R-5$. By the above,

$$R(R-9)=(R-5)^2$$

so that $R = 25$. From there, it’s easy.

The Power of a Point notion –which also relates not only chords, but tangents and secants that meet a point– is a handy one to know.

answered Apr 30, 2011 at 2:56

Here’s my brute force, minimal geometry solution.

Let the smaller circle have center $(c,0)$ and radius $r$. Let $E$ have coordinates $(0,e)$ and $D$ have coordinates $(-d,0)$. Let $R$ be the radius of the larger circle.

Then we have five unknowns and the five equations
$$
begin{eqnarray}
c^2+e^2 &=& r^2 \
c+d &=& r \
R &=& e+5 \
R &=& d+9 \
R &=& c+r
end{eqnarray}
$$
which can be easily solved. One finds $c=4.5$, $d=16$, $e=20$, $r=20.5$, and $R=25$.

answered Apr 29, 2011 at 20:34

Firstly,I am assuming that $O$ is the center of the inner circle.

Let,
$$CD=x$$
$$CE=y$$
$$OC=z$$
Now, from the figure we can write –
$$ 9+x=y+5 ……….(1) $$
$$ sqrt(y^2+z^2)=x+z……….(2) $$
$$ 18-(x+z)=9+x+z………..(3) $$
solving these equations we get-
$$x=16$$
$$y=20$$
$$z=4.5$$
so,
$$ R=x+9=16+9=25 $$
$$ r=x+z=16+4.5=20.5$$
Hence,the area of the crescent is
$$ Delta A =pi R^2 – pi r^2 =643.2410 $$

answered Jun 3, 2018 at 22:09