Как найти url скрипта

asked Jun 4, 2010 at 18:13

From http://feather.elektrum.org/book/src.html:

var scripts = document.getElementsByTagName('script');
var index = scripts.length - 1;
var myScript = scripts[index];

The variable myScript now has the script dom element. You can get the src url by using myScript.src.

Note that this needs to execute as part of the initial evaluation of the script. If you want to not pollute the Javascript namespace you can do something like:

var getScriptURL = (function() {
    var scripts = document.getElementsByTagName('script');
    var index = scripts.length - 1;
    var myScript = scripts[index];
    return function() { return myScript.src; };
})();

answered Jun 4, 2010 at 18:22

You can add id attribute to your script tag (even if it is inside a head tag):

<script id="myscripttag" src="http://site2.com/myscript.js"></script>

and then access to its src as follows:

document.getElementById("myscripttag").src

of course id value should be the same for every document that includes your script, but I don’t think it is a big inconvenience for you.

answered Aug 8, 2011 at 12:04

Everything except IE supports

document.currentScript

answered Aug 24, 2016 at 13:05

pery mimonpery mimon

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I wrote a class to find get the path of scripts that works with delayed loading and async script tags.

I had some template files that were relative to my scripts so instead of hard coding them I made created the class to do create the paths automatically. The full source is here on github.

A while ago I had use arguments.callee to try and do something similar but I recently read on the MDN that it is not allowed in strict mode.

function ScriptPath() {
  var scriptPath = '';
  try {
    //Throw an error to generate a stack trace
    throw new Error();
  }
  catch(e) {
    //Split the stack trace into each line
    var stackLines = e.stack.split('n');
    var callerIndex = 0;
    //Now walk though each line until we find a path reference
    for(var i in stackLines){
      if(!stackLines[i].match(/http[s]?:///)) continue;
      //We skipped all the lines with out an http so we now have a script reference
      //This one is the class constructor, the next is the getScriptPath() call
      //The one after that is the user code requesting the path info (so offset by 2)
      callerIndex = Number(i) + 2;
      break;
    }
    //Now parse the string for each section we want to return
    pathParts = stackLines[callerIndex].match(/((http[s]?://.+/)([^/]+.js)):/);
  }

  this.fullPath = function() {
    return pathParts[1];
  };

  this.path = function() {
    return pathParts[2];
  };

  this.file = function() {
    return pathParts[3];
  };

  this.fileNoExt = function() {
    var parts = this.file().split('.');
    parts.length = parts.length != 1 ? parts.length - 1 : 1;
    return parts.join('.');
  };
}

answered Mar 4, 2014 at 7:10

if you have a chance to use jQuery, the code would look like this:

$('script[src$="/myscript.js"]').attr('src');

answered Aug 14, 2013 at 3:03

Following code lets you find the script element with given name

var scripts = document.getElementsByTagName( 'script' );
        var len = scripts.length
        for(var i =0; i < len; i++) {
            if(scripts[i].src.search("<your JS file name") > 0 && scripts[i].src.lastIndexOf("/") >= 0) {
                absoluteAddr = scripts[i].src.substring(0, scripts[i].src.lastIndexOf("/") + 1);
                break;
            }
        }

answered Apr 2, 2014 at 5:54

AiryAiry

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function getScriptPath (hint) {
    if (  typeof document === "object" && 
          typeof document.currentScript === 'object' && 
          document.currentScript && // null detect
          typeof document.currentScript.src==='string' && 
          document.currentScript.src.length > 0) {
        return document.currentScript.src;
    }
    
    
    let here = new Error();
    if (!here.stack) {
        try { throw here;} catch (e) {here=e;}
    }
    if (here.stack) {
        
        const stacklines = here.stack.split('n');
        console.log("parsing:",stacklines);
        let result,ok=false;
        stacklines.some(function(line){
            if (ok) {
               const httpSplit=line.split(':/');
               const linetext = httpSplit.length===1?line.split(':')[0]:httpSplit[0]+':/'+( httpSplit.slice(1).join(':/').split(':')[0]);
               const chop = linetext.split('at ');
               if (chop.length>1) {
                   result = chop[1];
                   if ( result[0]!=='<') {
                      console.log("selected script from stack line:",line);               
                      return true;
                   }
                   result=undefined;
               }
               return false; 
            }
            ok = line.indexOf("getScriptPath")>0;
            return false;
        });
        return result;
    }
    
    if ( hint && typeof document === "object") {
       const script = document.querySelector('script[src="'+hint+'"]');
       return script && script.src && script.src.length && script.src;
    }
    
}
   
   console.log("this script is at:",getScriptPath ())

unsynchronizedunsynchronized

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answered Jun 4, 2010 at 18:16