Как составить уравнение реакции h3po4 koh

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

Examples

• KOH + H3Po4 + H2O = K3Po4*7H2O
• KOH + H3Po4 = K2(HPo4) + H2O
• Ni(NCS)2 + PPH3 = Ni(NCS)2(PPH3)2
• K3P + NaMnO4 + NaOH = Na2MnO4 + H2O + K3(PO4)
• CrBr3 + NH3 + H2O = Cr(OH)3 + NH4Br
• CH3CHClCH3 + KCN = KCl + CH3CH(CN)CH3
• CuSO4 + Al + NaCl = Al2(SO4)3 + Na2O4S + CuCl
• H2S + (CH3COO)3Al + H2O = CH3COOH + H2S + Al(OH)3
• ZnSO + NaOH = ZnOH + NaSO
• C2H4O2 + CuOH2 = H2O + Cu(CH3COOH)2
• Br + Na2SO4 = NaBr + SO4
• ZnSO4 + CuCl2 = CuCl2 + ZnSO4

Balance the equation KOH + H3Po4 = K3Po4 + H2O using the algebraic method or linear algebra with steps.

1. Label Each Compound With a Variable

   Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

   a KOH + b H₃Po₄ = c K₃Po₄ + d H₂O

2. Create a System of Equations

   Create an equation for each element (K, O, H, Po) where each term represents the number of atoms of the element in each reactant or product.

   K:	1a	+	0b	=	3c	+	0d
   O:	1a	+	0b	=	0c	+	1d
   H:	1a	+	3b	=	0c	+	2d
   Po:	0a	+	4b	=	4c	+	0d
   
   

3. Solve For All Variables

   Use substitution, Gaussian elimination, or a calculator to solve for each variable.

   • 1a – 3c = 0
   • 1a – 1d = 0
   • 1a + 3b – 2d = 0
   • 4b – 4c = 0

   Use your graphing calculator’s rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

   [ 1	 0	-3	 0	0]
   [ 1	 0	 0	-1	0]
   [ 1	 3	 0	-2	0]
   [ 0	 4	-4	 0	0]
   

   The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

   Simplify the result to get the lowest, whole integer values.

   • a = 3 (KOH)
   • b = 1 (H3Po4)
   • c = 1 (K3Po4)
   • d = 3 (H2O)

4. Substitute Coefficients and Verify Result

   Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

   3 KOH + H₃Po₄ = K₃Po₄ + 3 H₂O

   	Reactants	Products
   K	3	3	✔️
   O	3	3	✔️
   H	6	6	✔️
   Po	4	4	✔️

   Since there is an equal number of each element in the reactants and products of 3KOH + H3Po4 = K3Po4 + 3H2O, the equation is balanced.

Balance KOH + H3Po4 = K3Po4 + H2O by inspection or trial and error with steps.

The law of conservation of mass says that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To balance a chemical equation, every element must have the same number of atoms on each side of the equation.

1. Count the number of each element on the left and right hand sides

2. Multiply coefficients for compounds to balance out each element

1. K is not balanced. Add 2 molecule(s) of KOH to the reactant (left-hand) side to balance Potassium: 3KOH + H₃Po₄ = K₃Po₄ + H₂O

   	Reactants	Products
   K	3	3	✔️
   O	3	1	❌
   H	6	2	❌
   Po	4	4	✔️

2. O is not balanced. Add 2 molecule(s) of H₂O to the product (right-hand) side to balance Oxygen: 3KOH + H₃Po₄ = K₃Po₄ + 3H₂O

   	Reactants	Products
   K	3	3	✔️
   O	3	3	✔️
   H	6	6	✔️
   Po	4	4	✔️

3. Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

3KOH + H₃Po₄ = K₃Po₄ + 3H₂O

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